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A bag contains 7 marbles: 4 red, 2 yellow, and 1 green. Three
marbles are to be selected from the bag, one at a time, without
replacement. If the order of selection does not matter, how many
color combinations of the three marbles are possible?

Sagot :

121159idn

Answer:

Step-by-step explanation:

you have 7 reds of 14 total.

the 1st marble has 7 of 14 probability of being red

the 2nd has 6 of 13 of being red

the 3rd has 5 of 12 of being red

multiplying this out you have:

(7/14)*(6/13)*(5/12)=210/2184

THAT will condense down to 5/52 or 9.615%

this does assume not placing the balls back in between draws

if you do put them back in between draws you would have 7 of 14 chance each draw

that would give you by multiplying out

(7/14) * (7/14)* (7/14) = 343/2744

Found it online lol

that condenses to 1 of 8 or 12.5%

Found it online lol

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