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A sample of argon has a volume of 1.20 L at STP. If the temperature is increased to 22.0°C and the pressure is lowered to 0.800 atm, what will the new volume be, in L?

Sagot :

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Answer:

You have a pressure change and temperature change - you can use the combined gas law:

P1V1/T1 = P2V2/T2

Where P1 = 1am

          P2 = 0.8atm

T1 = 273K

T2 = 273 + 22 = 295K

V1 = 1.2lL

V2 = x

Explanation:

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