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The mass of Fe produced from the reaction is 0.938 g.
We'll begin by calculating the mass of Fe2O3 that reacted and the mass of Fe produced from the balanced equation.
3Zn + Fe₂O₃ —> 2Fe + 3ZnO
Molar mass of Fe₂O₃ = (56×2) + (16×3) = 160 g/mol
Mass of Fe₂O₃ from the balanced equation = 1 × 160 = 160 g
Molar mass of Fe = 56 g/mol
Mass of Fe from the balanced equation = 2 × 56 = 112 g
From the balanced equation above,
160 g of Fe₂O₃ reacted to produce 112 g of Fe.
Finally, we shall determine the mass of the Fe produced by 1.34 g of Fe₂O₃
From the balanced equation above,
160 g of Fe₂O₃ reacted to produce 112 g of Fe
Therefore,
1.34 g of Fe₂O₃ will react to produce = (1.34 × 112)/160 = 0.938 g of Fe
Thus, 0.938 g of Fe was produced from the reaction.
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