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A positive integer squared plus 3 times it’s consecutive integer is equal to 43

Sagot :

Maddiedsntknowidn

Answer:

the integer is 5

Step-by-step explanation:

x^2+3(x+1)=43

x^2+3x+3=43

x^2+3x+(9/4)=43-3+(9/4)

(x+(3/2))^2=42 1/4

x+(3/2)=sqrt(42 1/4)

x+(3/2)=6 1/2

x=(6 1/2)-(3/2)

x=5

check:

5^2+3(6)=43

25+18=43

43=43

Samuelthankgodidn

Answer:

5

Step-by-step explanation:

let positive integer be x

x² + 3(x+1)=43

x²+3x+3-43=0

x² + 3x - 40 = 0

x² + 8x - 5x - 40 = 0

x(x+8) - 5(x+8)=0

(x-5)(x+8)=0

x-5=0 or x+8=0

x=5. or x=-8

but the question says positive integer,

therefore, x=5

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