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[tex]y = 15x +9~~~~.....(i)\\\\y = \dfrac 12 x -20~~~ ....(ii)\\\\\\\text{Substitute equation (i) in equation (ii):}\\\\15x +9 = \dfrac 12 x -20\\\\\ \implies 9 +20 = \dfrac x2 - 15 x\\\\\implies 29 = -\dfrac{29 x}2\\\\\ \implies 1 = -\dfrac x 2\\\\\implies x= -2\\\\\text{Substitute}~ x=-2~ \text{in equation (i):}\\\\y = 15(-2) +9 = -30 +9 = -21\\\\\text{Hence}~ (x,y) = (-2,-21)[/tex]