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Trapezoid RSTU with vertices R(-5, 15), S(0, 10), T(-5, 5) and U(-15, 5): scale factor = 1/5, centered at the origin

Sagot :

SenorMathWizidn

Answer:

R'(-1,3) , S'(0,2) , T'(-1,1), U'(-3,1)

Step-by-step explanation:

To find the vertices of a point after a dilation simply multiply the x and y values of each given coordinate by the scale factor.

So to find the vertices of Trapezoid RSTU after a dilation centered at the origin with a scale factor of 1/5 we would multiply the x and y values of the given coordinates of Trapezoid RSTU by 1/5.

Given Coordinates:  R(-5, 15), S(0, 10), T(-5, 5) and U(-15, 5)

Scale Factor: 1/5

R(-5, 15) -----> ( -5 * 1/5 = -1 , 15 * 1/5 = 3 ) -----> (-1,3)

S(0,10) -----> ( 0 * 1/5 = 0 , 10 * 1/5 = 2 ) -----> (0,2)

T(-5,5) -----> ( -5 * 1/5 = -1 , 5 * 1/5 = 1 ) -----> (-1,1)

U(-15,5) -----> (-15 * 1/5 = -3 , 5 * 1/5 = 1 ) -----> (-3,1)

So the coordinates of Trapezoid RSTU after a dilation with a scale factor of 1/5 are R'(-1,3) , S'(0,2) , T'(-1,1), U'(-3,1)

Refer to the attached image for more validation

View image SenorMathWiz
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