From personal advice to professional guidance, IDNLearn.com has the answers you seek. Get accurate and detailed answers to your questions from our knowledgeable and dedicated community members.
The cook needs to add 21.333 ounces of water to obtain a 3 % concentration.
In matter of units, concentration equals to to the mass of cider vinegar ([tex]m_{c}[/tex]) divided by mass of water ([tex]m_{w}[/tex]), both expressed in ounces. A reduction on concentration implies that mass of cider vinegar remains constant while mass of water is increased.
Now we derive expressions for the initial and final concentrations for cider vinegar:
Initial concentration
[tex]c_{i} = \frac{m_{c}}{m_{w}+m_{c}}[/tex] (1)
Where:
Final concentration
[tex]c_{f} = \frac{m_{c}}{m_{c}+m_{w}'}[/tex] (2)
Where:
Then, if we know that [tex]c_{i} = 0.05[/tex], [tex]c_{f} = 0.03[/tex], [tex]m_{w}+m_{c} = 32\,oz[/tex] and [tex]m_{c}+m_{w}' = 32 + x[/tex], then the addition of water is:
[tex]0.05 = \frac{m_{c}}{32}[/tex] (1b)
[tex]0.03 = \frac{m_{c}}{32+x}[/tex] (2b)
Then we eliminate [tex]m_{c}[/tex] in (1b) and (2b):
[tex]0.05\cdot 32 = 0.03\cdot 32 + 0.03\cdot x[/tex]
[tex]0.02\cdot 32 = 0.03\cdot x[/tex]
[tex]x = 21.333\,oz[/tex]
The cook needs to add 21.333 ounces of water to obtain a 3 % concentration.
To learn more on concentrations, we kindly invite to check this question: https://brainly.com/question/492238