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Find the midpoint of PQ¯¯¯¯¯¯¯¯ with endpoints P(0, 2) and Q(6,−2). Then write an equation of the line that passes through the midpoint and is perpendicular to PQ¯¯¯¯¯¯¯¯ . This line is called the perpendicular bisector.

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Answer:

The midpoint of PQ is (3,0) and the equation if the line perpendicular to PQ is y=3/2(x-3).

Step-by-step explanation:

To find the midpoint, find the average of the x and y values. (0+6)/2=3 and (-2+2)/2=0

In order to make a perpendicular line, we must find the slope first of the original line.

(y2-y1)/(x2-x1) is the formula for slope

(-2-2)/(6-0)= -4/6=-2/3

Now we know the slope which is all we need to start making the equation using the point slope form which is y-y1=m(x-x1) (let m be slope) and we use the midpoint (3,0) as our point. since it is perpendicular, we will take the slope and flip it as well as change the sign

y-0=3/2(x-3) or y=3/2(x-3)

if you'd like, you can distribute and put it in slope intercept form

y=3/2x+9/2

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