We can find the slow by using the formula y2-y1/x2-x1. We have (-4, -6) and (2, 6). 6+6/2+4 is 12/6 which is 2. We need to put this into point slope form before putting this into slope-intercept form.
I will use the coordinates (2, 6).
y - 6 = 2(x - 2)
This gives us y - 6 = 2x - 4. We need to isolate y. This gives us y = 2x + 2.
I decided to use point slope form because it looks like the y-intercept is 2 and something tenths. However, the line is just off.
The answer is: y = 2x + 2
