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What is the equation of the line that passes through (-6,-2) and had a slope of -1/6

Sagot :

Chetankachanaidn

Answer:

[tex]y = -\frac{1}{6}x - 3[/tex]

Step-by-step explanation:

Slope Intercept Form :   [tex]y = mx + b[/tex]

Using our slope, -1/6, input it for m, then plug the point (-6, -2) for x and y

[tex]y = mx+b\\\\-2 = (-1/6)(-6) + b\\\\-2 = 1 + b\\\\b = -3[/tex]

Equation : [tex]y = -\frac{1}{6}x - 3[/tex]

-Chetan K

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