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If the concentration of KMnO4 was 0.0235 M, calculate the number of moles of MnO4- ions that completely reacted with the H2C2O4

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The number of moles of KMnO4 is  0.0006 moles.

The equation of the reaction is;

6 H^+(аq) + 2 МnO4^- (аq) + 5 Н2С2O4(аq) → 10 CO2 (g) + 8 H20 (l) + 2 Mn²+ (aq)

We can see that the volume of the titrant used = Final - initial burette reading

= 29.6 mL - 3.4 mL = 26.2 mL

Number of moles of H2C2O4 =  0.139 g/90 g/mol = 0.0015 moles

If 2 moles of  MnO4- reacts with 5 moles of H2C2O4

x moles of  MnO4- reacts with 0.0015 moles of H2C2O4

x =  2 moles ×  0.0015 moles / 5 moles

x = 0.0006 moles

Learn more: https://brainly.com/question/9743981

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