Connect with knowledgeable individuals and get your questions answered on IDNLearn.com. Our experts provide timely, comprehensive responses to ensure you have the information you need.

determine the bond type (NP, Polar, Ionic)

Determine The Bond Type NP Polar Ionic class=

Sagot :

Answer:

a. NP

b. NP

c. Polar

d. Ionic

e. Polar

Explanation:

The way I did it was using the electronegativity of the elements mentioned and subtracted the pairs. For non polar the difference is 0-0.4, for polar it’s 0.4-2.0, for ionic it’s >2.0. I included the chart I used to find the electonegativity for the elements below.

B: 2.04, P: 2.19, difference is 0.15, so NP

Be: 1.57, Si: 1.9, difference is 0.33, so NP

C: 2.55, Na: 0.93, difference is 1.62, so Polar

Li: 0.98, O: 3.44, difference is 2.46, so Ionic

Mg: 1.31, N: 3.04, difference is 1.73, so Polar

If you really want I can explain why electronegativity affects the types of bonds, just comment below

View image Elizzzz28

Answer:

Polar is the correct answer

Explanation:

#CarryOnLearning