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Answer:The cordinates of A and B are (-3.8, 5.2) and (7, -2).
Step-by-step explanation:From (1), we get x = (8 - 3y) / 2 ––(3)
Substitute (3) into (2),
2 [(8 - 3y) / 2]² + 3y² = 110
(8 - 3y)² + 3y² = 220
15y² - 48y - 156 = 0
Therefore y = 5.2, then x = (8 - 3×5.2) / 2 = -3.8
OR y = -2, then x = [8 - 3×(-2)] / 2 = 7
Answer:
The coordinates are A. (-3.8, 5.2) and B. (7, -2).
Step-by-step explanation:
At A and B the coordinates satisfy both equations so we solve simultaneously using substitution:
2x^2 + 3y^2 = 110
2x + 3y = 8
From the above equation
x = (8 - 3y)/2
So substituting for x in the first equation:
2 [(8-3y)/2]^2 + 3y^2 = 110
(8-3y)^2 / 2 + 3y^2 = 110
Multiply through by 2:
(8 - 3y)^2 + 6y^2 = 220
64 + 9y^2 - 48y + 6y^2 - 220 = 0
15y^2 - 48y - 156 = 0
3(5y^2 - 16y - 52) = 0
(5y - 26)(y + 2) = 0
y = 26/5, 2
y = 5.2, -2.
So substituting in 2x + 3y = 8
When y = -2:
2x - 6 = 8
2x = 14
x = 7.
When y = 5.2
2x + 3(5.2) = 8
2x = 8 - 15.6 = -7.6
x = -3.8.