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An engine has an energy input of 125 J, and 35 J of that energy is transformed into useful energy. What is the efficiency of the engine? 28% 35% 72% 90%.

Sagot :

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The efficiency of the engine at the given useful energy and input energy is 28%.

The given parameters:

  • Input energy of the engine, = 125 J
  • Useful energy of the engine, 35 J

The efficiency of the engine is defined as the ratio of the output energy (useful energy) to the input energy and it is calculated as follows;

[tex]efficiency\ = \frac{0ut put \ energy}{1nput \ energy} \times \ 100\%\\\\efficiency\ = \frac{35}{125} \times 100\%\\\\efficiency\ = 28 \ \%[/tex]

Thus, the efficiency of the engine at the given useful energy and input energy is 28%.

Learn more about efficiency of engine here: https://brainly.com/question/6751595

Answer:

ITS A

Explanation:

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