Find the best solutions to your problems with the help of IDNLearn.com's expert users. Our platform provides trustworthy answers to help you make informed decisions quickly and easily.

The quadratic function g(x)=ax^2+bx+c has the complex roots (10+i) and (10-i). You may assume that a=1.
What is the value of b?
What is the value of c?


Sagot :

The values are [tex]b=-20\text{ and }c=101[/tex]

The quadratic function, expressed in factored form is

[tex](x-(10+i))(x-(10-i))=g(x)[/tex]

Expanding and simplifying

[tex]g(x)=(x-(10+i))(x-(10-i))\\=x^2-x(10-i)-x(10+i)+(10+i)(10-i)\\=x^2-10x+xi-10x-xi+100-i^2\\=x^2-10x-10x+100+1\\=x^2-20x+101[/tex]

since

[tex]g(x)=ax^2+bx+c=x^2-20x+101[/tex]

we can equate coefficients of like-terms and conclude that

[tex]a=1,b=-20,c=101[/tex]

Learn more about quadratic equations here: https://brainly.com/question/12995618