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11) What volume will 0.75 mol of Oxygen gas (O2) occupy at 298 K and a pressure of 52.7 kPa?

Sagot :

Answer:

Volume = 35.3L

Explanation:

Use Ideal Gas Law (PV=nRT) and isolate for V (volume) by dividing both sides by P (pressure). You will then get the eqaution listed below and you can solve by using the method I used below.

V = nRT/P

V = (0.75kPa)(8.314)(298K)/(52.7kPa)

V = 1858.179/52.7

V = 35.3L

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