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Sodium carbonate (Na2CO3) reacts with acetic acid (CH3COOH) to form sodium acetate (NaCH3COO), carbon dioxide (CO2), and water (H2O). A chemist carries out this reaction in a bomb calorimeter. The reaction causes the temperature of a bomb calorimeter to decrease by 0. 985 K. The calorimeter has a mass of 1. 500 kg and a specific heat of 2. 52 J/g•K. What is the heat of reaction for this system? kJ.

Sagot :

Explanation:

Mass of bomb calorimeter, m = 1.5 kg = 1500 g

Temperature change of calorimeter, ΔT = - 0.985 K

Specific heat of calorimeter, c = 2.52 J/g K

To Find:

The heat of reaction for this system

Calculation:

The heat of reaction can be calculated by the given formula:

Q = mcΔT

⇒ Q = 1500 × 2.52 × (- 0.985)

⇒ Q = - 3723.3 J       (-ve sign shows heat is given by calorimeter)

- So the heat of reaction is -3723.3 J or -3.7233 kJ

Taking into account the definition of calorimetry, the heat of reaction for the system is  -3,723.3 J or -3.7233 kJ.

In first place, calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

In this way, between heat and temperature there is a direct proportional relationship.

The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body.

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • Q= ?
  • c= 2.52 [tex]\frac{J}{gK}[/tex]
  • m= 1.500 Kg= 1500 g
  • ΔT= -0.985 K is negative because the temperature decreases.

Replacing in the expression to calculate heat exchanges:

Q= 2.52[tex]\frac{J}{gK}[/tex]× 1500 g× (-0.985 K)

Solving:

Q= -3,723.3 J= -3.7233 kJ

Negative sign shows heat is given by calorimeter.

In summary, the heat of reaction for the system is  -3,723.3 J or -3.7233 kJ.

Learn more abour calorimetry:

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