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From a hot-air balloon, Grayson measures a 29^{\circ} ∘ angle of depression to a landmark that’s 1004 feet away, measuring horizontally. What’s the balloon’s vertical distance above the ground? Round your answer to the nearest hundredth of a foot if necessary.

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The balloon’s vertical distance above the ground is 556 feet

The set up will form a right triangle.

Given the following parameters

  • Angle of depression = 29 degrees
  • Horizontal distance = 1004 feet

To get the height above the ground, we will use the SOH CAH TOA identity as shown;

Opposite = h

Adjacent = 1004 feet

Tan theta = h/1004

Tan 29 = h/1004

h = 1004 tan 29

h = 1004(0.5543)

h = 556.52 feet

Hence the balloon’s vertical distance above the ground is 556 feet

Learn more on angle of depression here: https://brainly.com/question/23497407

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