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ABC is a right triangle. If AC = 7 and BC 8, find AB. Leave your answer in simplest radical form.

Sagot :

Mhanifaidn

Step-by-step explanation:

We don't know if AB is a hypotenuse or leg.

If AB is hypotenuse:

  • [tex]AB=\sqrt{AC^2+BC^2} =\sqrt{7^2+8^2} =\sqrt{49+64} =\sqrt{113}[/tex]

If AB is leg:

  • [tex]AB=\sqrt{BC^2-AC^2} =\sqrt{8^2-7^2} =\sqrt{64-49} =\sqrt{15}[/tex]

For base/Perpendicular

  • AB²=8²-7²
  • AB²=64-49
  • AB²=15
  • AB=√15

For Hypotenuse

  • AB²=8²+7²=64+49
  • AB²=113
  • AB=√113
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