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a -0.06 C charge is placed in a uniform electric field with a strength of 200 N/C. what is the magnitude and direction of the force on the charge​

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The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

To calculate the force on a charge in an electric field, we make use of the formula below.

Formula

F = E×Q .......................... Equation 1

Where:

  • F = Force on the charge
  • E = Electric Field
  • Q = charge

From the question,

Given:

  • E = 200 N/C
  • Q = -0.06 C

Substitute these values into equation 1

  • F = 200(-0.06)
  • F = -12 N

Note: The negative sign indicates that the force is in the direction negative of the electric field.

Hence, The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

Learn more about Electric Field here: https://brainly.com/question/14015797

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