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Answer:
C) x^5/2 +6x^3/2 +1
Step-by-step explanation:
The relevant rule of exponents is ...
a^b/a^c = a^(b-c)
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[tex]\dfrac{x^3+6x^2+x^{1/2}}{x^{1/2}}=x^{3-1/2}+6x^{2-1/2}+x^{1/2-1/2}=\boxed{x^{5/2}+6x^{3/2}+1}[/tex]