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a vessel contains 66 g co2 and 16 g o2 at a pressure of 10.0 atm. what is the partial pressure of co2?

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This question is providing the masses of carbon dioxide and oxygen gases at 10.0 atm as 66 g and 16 g respectively, and is asking for the partial pressure of the former which turns out to be 7.50 atm after doing the math.

Thus, we can start solving this problem with the Dalton's law approach, in order to make a relationship for the total pressure, partial pressure and mole fraction, which means we must first determine the mole fraction of carbon dioxide gas in the mixture as shown below:

[tex]x_{CO_2}=\frac{n_{CO_2}}{n_{CO_2}+n_{O_2}}[/tex]

Next, we calculate the moles of both gases by dividing the grams over the molar masses:

[tex]n_{CO_2}=\frac{66g}{44.01g/mol} =1.50mol\\\\n_{O_2}=\frac{16g}{32g/mol} =0.5mol[/tex]

Then, the mole fraction of carbon dioxide as the required one by plugging in the previously calculated moles:

[tex]x_{CO_2}=\frac{1.5}{1.5+0.5}=0.75[/tex]

Finally, we use the definition of the Dalton's law to calculate the partial pressure of carbon dioxide gas in the binary mixture:

[tex]P_{CO_2}=x_{CO_2}P\\\\P_{CO_2}=0.75*10.0atm\\\\P_{CO_2}=7.50 atm[/tex]

Learn more:

(Dalton's law) https://brainly.com/question/14119417

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