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Answer:
steps below
Step-by-step explanation:
h = 5t² + 8t + 3
5t² + 8t + (3-h) = 0
** ax²+bx+c=0 x= (-b±√b²-4ac)/2a
[tex]t=\frac{-8+\sqrt{64-4*5*(3-h)} }{10\\}\\ =\frac{-8+\sqrt{4+20h} }{10}\\ = -0.8 +0.2* \sqrt{1+5h}[/tex] ..... h≥3 to make t≥0