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Answer:
2x+5y=27
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(5-3)/(1-6)
m=2/-5
m=-2/5
y-y1=m(x-x1)
y-3=-2/5(x-6)
y-3=-2/5x+12/5
y=-2/5x+12/5+3
y=-2/5x+12/5+15/5
y=-2/5x+27/5
y-(-2/5x)=27/5
y+2/5x=27/5
5(y+2/5x)=5(27/5)
5y+2x=27
2x+5y=27