Answer:
0 & 0
Step-by-step explanation:
In order to find the answer to these two questions you need to use the slope formula, substitute, subtract, and simplify if needed.
[tex](-2,-5),(-2,-5) = (x^1,y^1),(x^2,y^2)[/tex]
Slope formula = [tex]m=\frac{y^2-y^1}{x^2-x^1}[/tex]
Substitute: [tex]\frac{-5--5}{-2--2} =[/tex]
[tex]\frac{-5--5}{-2--2} =-5--5 = 0[/tex]
[tex]-2--2 = -2+2=0[/tex]
[tex]= 0[/tex]
[tex](-3,-6),(-3,-6)=(x^1,y^1),(x^2,y^2)[/tex]
[tex]m=\frac{-6--6}{3--3}[/tex]
[tex]-6+6=0[/tex]
[tex]-3+3=0[/tex]
[tex]=0[/tex]
Hope this helps.
