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How many negative integers $m$ satisfy the inequality $\dfrac{3}{m} \le -\dfrac27$?

Sagot :

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Sqdancefanidn

Answer:

  10

Step-by-step explanation:

The restriction m < 0 means we can multiply by -7m/2 without changing the direction of the inequality symbol

  [tex]\dfrac{3}{m}\le-\dfrac27\\\\-\dfrac{21}{2}\le m\qquad m<0}[/tex]

Then the solution is the number of negative integer values between -10.5 and 0. There are 10 negative integer values of m that satisfy the inequality.

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