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The gas in a 250. mL piston experiences a change in pressure from 1.00 atm to 2.25 atm. What is the new volume (in mL) assuming the moles of gas and temperature are held constant?

Sagot :

Stephen46idn

Answer:

111.11 mL

Explanation:

Since the moles of gas and temperature are held constant the new volume can be found by using the formula for Boyle's law

[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

From the question

P1 = 1 atm

P2 = 2.25 atm

V1 = 250 mL

We have

[tex]V_2 = \frac{250 \times 1}{2.25} = \frac{250}{2.25} \\ = 111.1111111...[/tex]

We have the final answer as

111.11 mL

Hope this helps you

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