IDNLearn.com is designed to help you find reliable answers quickly and easily. Get accurate and comprehensive answers to your questions from our community of knowledgeable professionals.

The vertical and horizontal components of the velocity of a golf ball after being struck by a club are 4.0 m s1 and 5.0 m s respectively. Determine the magnitude and direction of the velocity of the golf ball. A 6.30 m s-1 B 6.35 m s-1 C 6.40 m s-1 D 6.45 m 5-1​

The Vertical And Horizontal Components Of The Velocity Of A Golf Ball After Being Struck By A Club Are 40 M S1 And 50 M S Respectively Determine The Magnitude A class=

Sagot :

The magnitude and direction of the velocity of the  golf ball is 6.4 m/s at 38.7⁰.

The given parameters:

  • Vertical component of the velocity, [tex]v_y = 4 \ m/s[/tex]
  • Horizontal component of the velocity, [tex]v_x = 5 \ m/s[/tex]

The magnitude of the resultant velocity of the golf ball is calculated as follows;

[tex]v= \sqrt{v_y^2 + v_x^2} \\\\v = \sqrt{4^2 + 5^2} \\\\v = 6.4 \ m/s[/tex]

The direction of the golf ball's velocity is calculated as follows;

[tex]\theta = tan^{-1} (\frac{v_y}{v_x} )\\\\\theta = tan^{-1}(\frac{4}{5} )\\\\\theta = 38.7 \ ^0[/tex]

Thus, the magnitude and direction of the velocity of the  golf ball is 6.4 m/s at 38.7⁰.

Learn more about magnitude and direction of velocity here: https://brainly.com/question/2456181