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The reading on the scale is equal to the weight of the student which is 646.8 N.
The given parameters;
The reading on the scale is determined by applying Newton's second law of motion as follows;
[tex]R = ma+ mg\\\\R = m(a + g)\\\\R = m(0 + g)\\\\R = mg[/tex]
The student is at rest and not accelerating, a =0
[tex]R = 66 \times 9.8\\\\R = 646.8 \ N[/tex]
Thus, the reading on the scale is equal to the weight of the student which is 646.8 N.
The complete question is below:
A 66 kg student stands on a very light, rigid board that rests on a bathroom scale at each end as shown in (Figure 1). what is the reading on the scale?
Learn more about Newton's second law here: https://brainly.com/question/3999427