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log(3+√5) + log(3 - √5) = ?​

Sagot :

Given that

log (3+√5) + log (3-√5)

We know that

log ab = log a + log b

⇛log [(3+√5)(3-√5)]

This is in the form of (a+b)(a-b)

Where a = 3 and b = √5

We know that

(a+b)(a-b) = a²-b²

⇛log [(3)²-(√5)²]

⇛log(9-5)

⇛log 4

Answer :- log (3+√5) + log (3-√5) = log 4

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