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Given that
log (3+√5) + log (3-√5)
We know that
log ab = log a + log b
⇛log [(3+√5)(3-√5)]
This is in the form of (a+b)(a-b)
Where a = 3 and b = √5
We know that
(a+b)(a-b) = a²-b²
⇛log [(3)²-(√5)²]
⇛log(9-5)
⇛log 4
Answer :- log (3+√5) + log (3-√5) = log 4
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