Rianemcintyre07idn
Answered

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How many solutions does the following equation have? 10x-1=10x+4

Sagot :

  • Your answer is no solution.
  • Because if we transpose 10x to the left hand side with a change in the symbol, then it will become 0.
  • 10x - 1 = 10x +4
  • or, 10x - 10x = 4 + 5
  • or, 0 = 9
  • Hence, the equation has no solution.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Fitaxc27idn

Answer:

10x-1=10x+4

10x-10x=4+1

x=5

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