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The time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.
The given parameters;
Mass of the first object, m1 = 1 kg
Mass of the second object, m2 = 5 kg
The final velocity of the objects during the downward motion is calculated as follows;
[tex]v_f = v_0 + gt\\\\v_f = 0 + gt\\\\\v_f = gt[/tex]
The time of motion of the object from the given height is calculated as;
[tex]h = v_0 t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\gt^2 = 2h\\\\t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} }[/tex]
The time of motion of each object is independent of mass of the object.
Thus, the time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.
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