Answered

IDNLearn.com: Your reliable source for finding precise answers. Find the answers you need quickly and accurately with help from our knowledgeable and experienced experts.

The chemical equation below shows the combustion of methane (ch4). Ch4 + 2o2 right arrow. Co2 + 2h2o the molar mass of oxygen gas (o2) is 32. 00 g/mol. The molar mass of carbon dioxide (co2) is 44. 01 g/mol. What mass of co2, in grams, will form when 8. 94 g o2 completely react?.

Sagot :

CintiaSalazaridn

Taking into account the reaction stoichiometry, 6.15 grams of CO₂ are formed when 8.94 grams of O₂ reacts completely.

In first place, the balanced reaction is:

CH₄ + 2 O₂  → CO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CH₄: 1 mole
  • O₂: 2 moles
  • CO₂: 1 mole
  • H₂O: 2 moles

The molar mass of the compounds is:  

  • CH₄: 16.04 g/mole
  • O₂: 32 g/mole
  • CO₂: 44.01 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • CH₄: 1 mole× 16.04 g/mole= 16.04 grams
  • O₂: 2 moles× 32 g/mole= 64 grams
  • CO₂: 1 mole× 44.01 g/mole= 44.01 grams
  • H₂O: 2 moles× 18 g/mole= 36 grams

Then the following rule of three can be applied: if by reaction stoichiometry 64 grams of O₂ form 44.01 grams of CO₂, 8.94 grams of O₂ form how much mass of CO₂?

[tex]mass of CO_{2} =\frac{8.94 grams of O_{2} x44.01 grams of CO_{2} }{64 grams of O_{2}}[/tex]

mass of CO₂= 6.15 grams

Finally, 6.15 grams of CO₂ are formed when 8.94 grams of O₂ reacts completely.

Learn more about reaction stoichiometry:  

  • brainly.com/question/24741074
  • brainly.com/question/24653699
  • brainly.com/question/23871710
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.