Answered

Get the answers you've been looking for with the help of IDNLearn.com's expert community. Get accurate and detailed answers to your questions from our knowledgeable and dedicated community members.



ROCKETS The height in feet of a rocket t seconds after launch is modeled
by h(t) =–16t2 + 72t. Find its average speed from 3 to 4 seconds.
F-56 ft/s
G40 ft/s H 40 ft/s
J 56 ft/s

Sagot :

Akposevictoridn

The average speed of the rocket from 3 to 4 seconds after launch is: -40 ft/s

Given the equation as a model, h(t) =–16t² + 72t.

Average speed from 3 to 4 seconds = [tex]\frac{h(4) - h(3)}{4 - 3}[/tex]

Find h(4):

h(t) =–16t² + 72t

  • Substitute 4 for t in the equation h(t) =–16t² + 72t

h(4) = -16(4)² + 72(4)

h(4) = -256 + 288

h(4) = 32

Find h(3):

h(t) = -16t² + 72t

  • Substitute 3 for t in the equation h(t) =–16t² + 72t

h(3) = -16(3)² + 72(3)

h(3) = -144 + 216

h(3) = 72

Plug in the value into  [tex]\frac{h(4) - h(3)}{4 - 3}[/tex]:

average speed from 3 to 4 secs = [tex]\frac{32 - 72}{4 - 3} = -40[/tex]

Therefore, the average speed of the rocket from 3 to 4 seconds after launch is: -40 ft/s

Learn more about average rate of change on:

https://brainly.com/question/11627203

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. IDNLearn.com is your go-to source for accurate answers. Thanks for stopping by, and come back for more helpful information.