Answered

From simple questions to complex issues, IDNLearn.com has the answers you need. Ask your questions and receive detailed and reliable answers from our experienced and knowledgeable community members.

A normal appearing couple is found to be heterozygous recessive for albinism. Both have the genotype Aa. The gene responsible for albinism is recessive to the normal pigment-producing gene. What are the chances of their children being albino? 3:4 children will be albino. All children will be albino. 1:4 children will be albino.

Sagot :

Dieneidn
1:4 children will be albino.
If you make a Punnett square with Aa and Aa, you'll see that the ratios are:
AA:Aa:aa=1:2:1
so the ratio of aa out of the total is 1/(1+2+1)=1/4
Annykslidn

Answer:

1:4 children will be albino.

Explanation:

Each parent has the Aa genotype and the genotype of a person with albinism is aa. Therefore, to find out what the chances of the children of this pair are albinos, we must do the Square of Punnett and verify how many times the genotype aa appears.

As you can see in the square below, there are 4 possibility of genotypes for the children of this couple. Of these 4, only 1 genotype shows the aa configuration. So the odds of the couple's children being albinos is 1: 4.

View image Annyksl
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. Your questions deserve reliable answers. Thanks for visiting IDNLearn.com, and see you again soon for more helpful information.