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1-4y^2 = 0
Solve the equation

Sagot :

WarCrimesIncarnateidn

Answer: y = 1/2 or y = -1/2

Step-by-step explanation:

First move the 1 to the side with the 0

-4y^2 = -1 // -1 because when you move a number to the other side of the equation  you have to multiply -1

Then divide by -4 on each side

y^2 = 1/4

square root each side

|y| = 1/2 // sq rt y^2 becomes an absolute value because when you square root a square it automatically becomes an absolute value

so the answer would be y = 1/2 or -1/2

to check just put it into the equation as y. Both work.

Silirobert15idn

EXPLANATION:

 [tex]1-4y^2=0\\1^2-(2y)^2=0\\(1-2y)(1+2y)=0\\[/tex]

⇒  [tex]1-2y=0[/tex]   or   [tex]1+2y=0\\[/tex]

⇒ [tex]2y=1[/tex]  or   [tex]2y=-1\\[/tex]

⇒ [tex]y= \frac{1}{2}[/tex]  or  [tex]y=\frac{-1}{2}[/tex]

P/s:   [tex]A^2-B^2=(A-B)(A+B)[/tex]

Ok done. Thank to me :>

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