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Answer:
A. The photographer will get to the jeep before the rhinocerous
Explanation:
Δv = Δd/Δt
we can rearrange for time
Δt = Δd/Δv
For the photographer:
Distance is 10m and moves at 6m/s
Δt = 10m/6m/s
Δt = 1.67s
For the rhinocerous
Distance is 16m and moves at 8m/s
Δt = 16m/8m/s
Δt = 2.00s
The distances were to get to the jeep, the photographer makes it to the jeep in a shorter amount of time than the rhino