Answered

Get expert insights and community support for your questions on IDNLearn.com. Receive prompt and accurate responses to your questions from our community of knowledgeable professionals ready to assist you at any time.

Congratulations! You’ve recently received a promotion from work. Your new job is to fill rooms with certain gases. A room is found to measure 9.00 feet wide by 12.0 feet long and 10.0 feet high. Your first assignment is to fill this room with a gas that has a density of 0.88543 kg/m3. Unfortunately your boss is asking you to make the gas (if you know what I mean). How many grams of this gas are required to fill the room? (1m3 = 35.3147 ft3) (Round to the appropriate sig fig)

Sagot :

Asuwafohjamesidn

The amount of gas required to fill the room is 27076.4 g

To calculate the grams of the gas that will fill the room, we make use of the formula below

⇒ Formula:

  • D = m/V....................... Equation 1

⇒ Where:

  • D = Density of the gas
  • m = mass of the gas
  • V = Volume of the room

⇒ make m the subject of the equation

  • m = DV................... Equation 2

From the question,

⇒ Given:

  • D = 0.88543 kg/m³
  • V = Volume of a cubiod = Length×Width×Height = 9×12×10 = 1080 ft³

⇒ Converting the volume from ft³ to m³

  • V = 1080/35.3147
  • V = 30.58 m³

Substitute these values into equation 2

  • m = 0.88543(30.58)
  • m = 27.0764 kg
  • m ≈ 27076.4 g

Hence, The amount of gas required to fill the room is 27076.4 g

Learn more about density here: https://brainly.com/question/11107994

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.