Answered

Find expert advice and community support for all your questions on IDNLearn.com. Discover comprehensive answers from knowledgeable members of our community, covering a wide range of topics to meet all your informational needs.

baseball outfielder throws a baseball of mass 0.15 kg at a speed of 40 m/s and initial angle of 30. What
is the kinetic energy of the baseball at the highest point of the trajectory? Answer: 90 J

Sagot :

Trancescientidn

Explanation:

At the top of the the ball's trajectory, there is only the horizontal component of the initial velocity, which is [tex]v_0\cos30,[/tex] so the kinetic energy of the ball at this point is

[tex]KE = \frac{1}{2}m(v_0\cos30)^2[/tex]

[tex]\;\;\;\;\;= \frac{1}{2}(0.15\:\text{kg})[(40\:\text{m/s})\cos30]^2[/tex]

[tex]\;\;\;\;\;= 90\:\text{J}[/tex]

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for solutions ends here at IDNLearn.com. Thank you for visiting, and come back soon for more helpful information.