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12/sqrt2 + sqrt18 in the form bsqrt2 where b is an integer

Sagot :

Answer:

[tex] \sqrt[15]{2} [/tex]

Step-by-step explanation:

[tex] \sqrt[12]{2} + \sqrt{18} [/tex]

[tex] \sqrt[12]{2} + \sqrt[3]{2} [/tex]

[tex] \sqrt[15]{2} [/tex]

pls tag brainiest If this was helpful