Explore IDNLearn.com to discover insightful answers from experts and enthusiasts alike. Join our interactive Q&A community and access a wealth of reliable answers to your most pressing questions.
Sagot :
Answer:
cos3x+tan3x=0
⟹cos3x=−tan3x
⟹cos3x=−sin3xcos3x
⟹cos23x=−sin3x
⟹1−sin23x=−sin3x
⟹sin23x−sin3x−1=0
This is a quadratic equation in sin3x.
sin3x=−(−1)±(−1)2−4×1×(−1)−−−−−−−−−−−−−−−−−√2×1
sin3x=1±5–√2
If x takes real values, the upper sign must be rejected.
sin3x=1−5–√2
⟹3x=nπ+(−1)nsin−11−5–√2
⟹x=13[nπ+(−1)nsin−11−5–√2]
Step-by-step explanation:
Hope this kind of helps
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! IDNLearn.com is committed to providing accurate answers. Thanks for stopping by, and see you next time for more solutions.
