Answered

Get detailed and accurate responses to your questions on IDNLearn.com. Get accurate and detailed answers to your questions from our dedicated community members who are always ready to help.

See the picture :D. Please help fast.

See The Picture D Please Help Fast class=

Sagot :

Answer:

In ΔABD and ΔAEC

BE=DC (given) …(i)

Subtracting DE from both side of (i), we get

BE–DE=DC–DE

BD=EC

AB=AC (given)

∠B=∠C  (angle opposite to equal sides are equal)

Similarly, ΔABD≅ΔAEC

AD=AE (by c.p.c.t)

Hence proved

Mhanifaidn

Answer:

  • See below

Step-by-step explanation:

Consider triangles ABE and ACD:

  • ∠BAC ≅ ∠CAB, common angle, congruent to itself
  • ∠ABE ≅ ∠ACD, same arc DE intercepted
  • AB = AC, given

According to above congruence statements, we can conclude:

  • ΔABE ≅ ΔACD as per ASA postulate, since two angles and the included side are congruent

Since the triangles are congruent, we have:

  • BE = CD as corresponding sides of congruent triangles
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Your search for answers ends at IDNLearn.com. Thank you for visiting, and we hope to assist you again soon.