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See the picture :D. Please help fast.

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Sagot :

Answer:

In ΔABD and ΔAEC

BE=DC (given) …(i)

Subtracting DE from both side of (i), we get

BE–DE=DC–DE

BD=EC

AB=AC (given)

∠B=∠C  (angle opposite to equal sides are equal)

Similarly, ΔABD≅ΔAEC

AD=AE (by c.p.c.t)

Hence proved

Mhanifaidn

Answer:

  • See below

Step-by-step explanation:

Consider triangles ABE and ACD:

  • ∠BAC ≅ ∠CAB, common angle, congruent to itself
  • ∠ABE ≅ ∠ACD, same arc DE intercepted
  • AB = AC, given

According to above congruence statements, we can conclude:

  • ΔABE ≅ ΔACD as per ASA postulate, since two angles and the included side are congruent

Since the triangles are congruent, we have:

  • BE = CD as corresponding sides of congruent triangles
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