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A box contains 6 bags of Doritos and 4 bags of Cheetos. Another box contains 5 cans of Coke and 3 cans of Pepsi. If you randomly pick one thing out of the first box and one thing out of the second box, what is the probability you will end up with Doritos and Coke?


A 2/5


B 1/4


C 1/2


D 3/8

Sagot :

Answer:

Step-by-step explanation:

okay so basically 6+4=10 so the probability of doritos is 3/5 and 5+3=8 so the probabliliy is 5/8. I think the answer is A. but i 100% could be wrong, im sorry if i am

The probability you will end up with Doritos and Coke is; P(Doritos and Coke) = 0.375

How to find the probability?

We are told the components of the box are;

6 bags of Doritos

4 bags of Cheetos

Second box contains;

5 cans of Coke.

3 cans of Pepsi.

Probability of picking doritos in first box = 6/10

Probability of picking coke in second box = 5/8

Thus;

P(Doritos and Coke) = 6/10 * 5/8

P(Doritos and Coke) = 0.375

Read more about Probability at; https://brainly.com/question/251701

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