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A roller coaster is released from the top of a track that is 57 m high. Find the roller coaster speed when it reaches ground level.

Sagot :

Leenaidn

Hi there!

Assuming the track is frictionless:

[tex]E_i = E_f\\\\PE = KE\\\\mgh = \frac{1}{2}mv^2[/tex]

Cancel out the masses and rearrange to solve for velocity:

[tex]gh = \frac{1}{2}v^{2}\\\\v = \sqrt{2gh}\\\\[/tex]

Plug in the given height and let g = 9.8 m/s²:

[tex]v = \sqrt{2(9.8)(57)} = \boxed{33.42 m/s}[/tex]

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