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Find the vertex of
G(x)=x^2+4 x


Sagot :

Answer:

(- 2, - 4 )

Step-by-step explanation:

The x- coordinate of the vertex is calculated as

x = - [tex]\frac{b}{2a}[/tex]

g(x) = x² + 4x

with a = 1, b = 4 , then

x = - [tex]\frac{4}{2}[/tex] = - 2

Substitute x = - 2 into g(x) for corresponding y- coordinate

g(- 2) = (- 2)² + 4(- 2) = 4 - 8 = - 4

vertex = (- 2, - 4 )