Berry102idn
Answered

IDNLearn.com makes it easy to find accurate answers to your specific questions. Ask anything and get well-informed, reliable answers from our knowledgeable community members.

Consider the following reaction:
2Al (s) + 6HCl (aq) → 2AlCl3 (aq) + 3H2 (g).
A 0.080 mole piece of aluminum reacted completely in 20 s.
The rate of formation of hydrogen gas is:

Sagot :

Okpalawalter8idn

The rate of formation of hydrogen gas is:

  • [tex]0.006mol/s[/tex]

Chemical equation

2Al (s) + 6HCl (aq) → 2AlCl3 (aq) + 3H2 (g).

According to the reaction,

2mol Al can produce 3mol [tex]H_2[/tex]

0.08mol Al = [tex]\frac{3*0.08}{2}mol H_2[/tex]

[tex]= 0.12mol H_2[/tex]

so we can say,

in 20s, 0.12mol H_2 will be produced

Hydrogen Formation

The rate of formation of [tex]H_2[/tex] = [tex]\frac{mol of H_2 formed}{time taken to form}[/tex]

[tex]= \frac{0.12}{20}\\\\= 0.006mol/s[/tex]

For more information on formation of hydrogen, visit

https://brainly.com/question/9791360?referrer=searchResults

Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.