Answered

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with a mean of 32 minutes and a standard deviation of 5 minutes. What is the probability that a randomly selected customer will have to wait less than 21 minutes, to the nearest thousandth?

Sagot :

Answer:

1.39%

Step-by-step explanation:

(21 - 32) / 5 = -2.2 z score

= 0.0139 so there is a 1.39% probability

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