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Sagot :
Using probability concepts, it is found that she could use a binomial distribution with [tex]n = 3[/tex] and [tex]p = \frac{1}{3}[/tex] to estimate the probability that the next three books she selects are all literature.
For each book she selects, there are only two possible outcomes, either it is a literature book, or it is not. The probability of a book selected being a literature book is independent of any other book, hence, the binomial distribution is used to solve this question.
Binomial probability distribution
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- Next three books selected, hence [tex]n = 3[/tex].
- She has an equal number of fiction, literature, and poetry books, hence, the probability of each book selected being a literature book is [tex]p = \frac{1}{3}[/tex]
Hence, she could use a binomial distribution with [tex]n = 3[/tex] and [tex]p = \frac{1}{3}[/tex] to estimate the probability that the next three books she selects are all literature.
You can learn more about the binomial distribution at https://brainly.com/question/24863377
Answer:
Number Cube
Let 1, 6= Literature
Let 2, 4= Fiction
Let 3, 5= Poetry
Roll the cube 3 times, Repeat
It has to be equal probability for all three
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