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A 1500 kg car takes a 50-m-radius unbanked curve at 15 m/s.

What is the size of the friction force on the car?

Sagot :

Leenaidn

Hi there!

Since the car is not accelerating in the vertical direction, the only net force acting on the car is in the horizontal direction.

This is the force due to friction, which is also providing the centripetal force. So:

[tex]\Sigma F_x = F_f[/tex]

[tex]\frac{mv^2}{r} = F_f\\\\[/tex]

m = mass (kg)

v = velocity (m/s)

r = radius (m)

Plug in the given values:

[tex]F_f = \frac{1500(15^2)}{50} = \boxed{6750 N}[/tex]

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