IDNLearn.com connects you with a community of knowledgeable individuals ready to help. Ask your questions and receive prompt, detailed answers from our experienced and knowledgeable community members.
Sagot :
This is a basic algebraic equation
And will be using PEMDAS to solve
P: Parentheses
E: exponents
M: Multiplication
D: Division
A: Addition
S: Subtraction
If you are unaware of PEMDAS this is the order at which you solve algebraic equation. So start from “P” and end with “S”
X= 2/3
2/3^3 Times 3 Divided by 2/9 + 9(2/3) - 7 - 6(2/3)
Now, personal I’d choose to convert fractions to decimals to simplify solving the equation. I doubt this is the only way to solve for the equation but I find this is the easiest
To convert a fraction to decimal you divide the numerator by the denominator.
So 2/3 is 0.666667
And
That means 2/9 is 0.222222
0.666667^3*3/0.222222+9(0.666667)-7-6(0.666667)
Making you answer roughly -0.999989
Hope this helps, but I’m not sure if this is completely right or not
And will be using PEMDAS to solve
P: Parentheses
E: exponents
M: Multiplication
D: Division
A: Addition
S: Subtraction
If you are unaware of PEMDAS this is the order at which you solve algebraic equation. So start from “P” and end with “S”
X= 2/3
2/3^3 Times 3 Divided by 2/9 + 9(2/3) - 7 - 6(2/3)
Now, personal I’d choose to convert fractions to decimals to simplify solving the equation. I doubt this is the only way to solve for the equation but I find this is the easiest
To convert a fraction to decimal you divide the numerator by the denominator.
So 2/3 is 0.666667
And
That means 2/9 is 0.222222
0.666667^3*3/0.222222+9(0.666667)-7-6(0.666667)
Making you answer roughly -0.999989
Hope this helps, but I’m not sure if this is completely right or not
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.